An electron at point in figure has a speed of v0 = 1.41 x 106 m/s.Finda) the magnitude and direction of the magnetic field that willcause the electron to follow the semicircular path from A to Bandb) the time required for the electron to move from A to B.

An electron moves in circular motion in a uniform magnetic field.P velocityThe velocity of the electron at point P is 6.8 × 105 m s-1 in the direction shown.The magnitude of the magnetic field is 8.5 T.(a) State the direction of the magnetic field.

Consider an electron moving with a speed of 8.60 106 m/s at right angles to a constant magnetic field, with B = 1.4 T. What is the radius of the circular path of the electron?

An electron is launched with velocityv in a uniformmagnetic fieldB . The angle betweenv andB liesbetween 0 and2 . Its velocity vectorv returns to itsinitial value in a time interval of

An electron moving at right angles to a 0.10-T magnetic field experiences an acceleration of 6.0x10'5 m/s. (a) What's its speed? (b) By how much does its speed change in 1 ns?

An electron experiences a magnetic force of magnitude 4.60 x 10-15 N when moving at an angleof 600 with respect to a magnetic field of magnitude 3.50 x 10-3 T. Find the speed of theelectron.