. Calculate the osmotic pressure (in atmospheres) of a solution containing 1.60 g ethylene glycol (C2H6O2) in 51.0 mL of solution at 25∘C.
Question
. Calculate the osmotic pressure (in atmospheres) of a solution containing 1.60 g ethylene glycol (C2H6O2) in 51.0 mL of solution at 25∘C.
Solution
To calculate the osmotic pressure of a solution, we can use the formula:
π = (n/V)RT
Where: π = osmotic pressure n = number of moles of solute V = volume of solution in liters R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature in Kelvin
First, we need to calculate the number of moles of ethylene glycol (C2H6O2) in the solution. To do this, we can use the molar mass of ethylene glycol, which is 62.07 g/mol.
Number of moles = mass of solute / molar mass Number of moles = 1.60 g / 62.07 g/mol
Next, we need to convert the volume of the solution from milliliters to liters. Since 1 mL is equal to 0.001 L, we have:
Volume of solution = 51.0 mL * 0.001 L/mL
Now, we can substitute the values into the osmotic pressure formula:
π = (n/V)RT
Remember to convert the temperature from Celsius to Kelvin by adding 273.15:
Temperature in Kelvin = 25°C + 273.15
Finally, calculate the osmotic pressure:
π = (n/V)RT
Make sure to round the final answer to the appropriate number of significant figures.
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