The osmotic pressure of a solution of 0.800 g of sucroseC12H22O11, in 150 g water at 35oC is:
Question
The osmotic pressure of a solution of 0.800 g of sucroseC12H22O11, in 150 g water at 35oC is:
Solution
To solve this problem, we need to use the formula for osmotic pressure:
Π = n/V * R * T
where:
- Π is the osmotic pressure,
- n is the number of moles of the solute,
- V is the volume of the solvent in liters,
- R is the ideal gas constant (0.0821 L·atm/(K
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