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14 The reaction between sulfur dioxide and oxygen is reversible.2SO 2(g) + O 2(g) 2SO 3(g) Kc = 280 mol–1 dm3 at 1000 KIn an equilibrium mixture at 1000 K the sulfur trioxide concentration is 6.00 mol dm–3.The sulfur dioxide concentration is twice the oxygen concentration.What is the sulfur dioxide concentration?A 0.175 mol dm–3B 0.252 mol dm–3C 0.318 mol dm–3D 0.636 mol dm–3

Question

14 The reaction between sulfur dioxide and oxygen is reversible.2SO 2(g) + O 2(g) 2SO 3(g) Kc = 280 mol–1 dm3 at 1000 KIn an equilibrium mixture at 1000 K the sulfur trioxide concentration is 6.00 mol dm–3.The sulfur dioxide concentration is twice the oxygen concentration.What is the sulfur dioxide concentration?A 0.175 mol dm–3B 0.252 mol dm–3C 0.318 mol dm–3D 0.636 mol dm–3

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Solution

The equilibrium constant expression for the reaction is:

Kc = [SO3]^2 / ([SO2]^2 * [O2])

We know that [SO3] = 6.00 mol dm^-3, [SO2] = 2[O2], and Kc = 280 mol^-1 dm^3.

Substituting these values into the equilibrium constant expression gives:

280 = (6)^2 / ((2[O2])^2 * [O2])

Solving this equation for [O2] gives [O2] = 0.318 mol dm^-3.

Since [SO2] = 2[O2], the concentration of SO2 is 2 * 0.318 mol dm^-3 = 0.636 mol dm^-3.

So, the sulfur dioxide concentration is 0.636 mol dm^-3 (Option D).

This problem has been solved

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