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An equilibrium mixture of O2, SO3, and SO2 contain equal concentrations of SO2 and SO3. Calculate the concentration of SO3 if the Keq = 220. 2SO2 (g) + O2 (g) → 2SO3 (g)

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An equilibrium mixture of O2, SO3, and SO2 contain equal concentrations of SO2 and SO3. Calculate the concentration of SO3 if the Keq = 220. 2SO2 (g) + O2 (g) → 2SO3 (g)

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Solution 1

To solve this problem, we need to use the equilibrium constant expression for the reaction. The equilibrium constant expression is given by:

Keq = [SO3]^2 / ([SO2]^2 * [O2])

Given that the concentrations of SO2 and SO3 are equal, we can denote them as [x]. The equation then simplifies to:

220 = [x]^2 / ([x]^2 * [O2])

We can simplify this further to:

220 = 1 / [O2]

Solving for [O2], we get:

[O2] = 1 / 220

Therefore, the concentration of O2 is 0.00455 M.

Since the concentrations of SO2 and SO3 are equal, the concentration of SO3 is also 0.00455 M.

This problem has been solved

Solution 2

To solve this problem, we need to use the equilibrium constant expression for the reaction. The equilibrium constant expression for this reaction is:

Keq = [SO3]^2 / ([SO2]^2 * [O2])

Given that the concentrations of SO2 and SO3 are equal, we can denote their concentration as x. The equation then simplifies to:

Keq = x^2 / (x^2 * x) = x^2 / x^3 = 1/x

Solving for x, we get:

x = 1/Keq

Substituting the given value of Keq = 220, we get:

x = 1/220 = 0.004545 mol/L

Therefore, the concentration of SO3 is 0.004545 mol/L.

This problem has been solved

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