What will be the final elements on the queue and stack if the following sequence of operations are executed? Queue q = new Queue(); Stack s = new Stack(); q.push("a"); s.push("b"); q.push("c"); s.push("d"); s.push( q.pop() ); q.push( s.peek() ); q.push( s.pop() );
Question
What will be the final elements on the queue and stack if the following sequence of operations are executed? Queue q = new Queue(); Stack s = new Stack(); q.push("a"); s.push("b"); q.push("c"); s.push("d"); s.push( q.pop() ); q.push( s.peek() ); q.push( s.pop() );
Solution
The operations are executed as follows:
q.push("a"): "a" is added to the queue.s.push("b"): "b" is added to the stack.q.push("c"): "c" is added to the queue.s.push("d"): "d" is added to the stack.s.push( q.pop() ): The front element of the queue, which is "a", is removed from the queue and added to the stack.q.push( s.peek() ): The top element of the stack, which is "a", is added to the queue.q.push( s.pop() ): The top element of the stack, which is "a", is removed from the stack and added to the queue.
So, the final elements in the queue are "c", "a", "a" (from front to back), and the final elements in the stack are "d", "b" (from top to bottom).
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