A body is dropped from a tower with zero velocity reaches the ground in 10s. The height of the tower is about :(given : g = 10 m/s2)
Question
A body is dropped from a tower with zero velocity reaches the ground in 10s. The height of the tower is about :(given : g = 10 m/s2)
Solution
To find the height of the tower, we can use the equation of motion:
h = ut + 0.5gt^2
where:
- h is the height of the tower,
- u is the initial velocity,
- t is the time it takes for the body to reach the ground, and
- g is the acceleration due to gravity.
Given in the problem, u = 0 (since the body is dropped, not thrown), t = 10s, and g = 10 m/s^2.
Substituting these values into the equation, we get:
h = 010 + 0.510*(10^2) h = 0 + 0.510100 h = 0 + 500 h = 500 m
So, the height of the tower is approximately 500 meters.
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