Sure, we can solve this problem using the physics equation for motion:

v² = u² + 2gs

where:
v is the final velocity,
u is the initial velocity,
g is the acceleration due to gravity, and
s is the distance.

Given:
u = 0 (since the stone is released from rest),
g = 9.8 m/s² (approximate value of gravity on Earth), and
s = 19.6 m (height of the tower).

Substituting these values into the equation, we get:

v² = 0 + 2*9.8*19.6
v² = 384.16

Taking the square root of both sides to solve for v, we get:

v = sqrt(384.16)
v = 19.6 m/s

So, the final velocity of the stone just before touching the ground is 19.6 m/s.

Question

Sure, we can solve this problem using the physics equation for motion:

v² = u² + 2gs

where:
v is the final velocity,
u is the initial velocity,
g is the acceleration due to gravity, and
s is the distance.

Given:
u = 0 (since the stone is released from rest),
g = 9.8 m/s² (approximate value of gravity on Earth), and
s = 19.6 m (height of the tower).

Substituting these values into the equation, we get:

v² = 0 + 2*9.8*19.6
v² = 384.16

Taking the square root of both sides to solve for v, we get:

v = sqrt(384.16)
v = 19.6 m/s

So, the final velocity of the stone just before touching the ground is 19.6 m/s.

Knowee AI · Accepted Answer