A stone is released from the top of a tower of height 980 m. Calculate its velocity after 3 seconds. (Take g = 9.8 m/s2)
Question
A stone is released from the top of a tower of height 980 m. Calculate its velocity after 3 seconds. (Take g = 9.8 m/s2)
Solution
To calculate the velocity of the stone after 3 seconds, we can use the equation of motion:
v = u + gt
where: v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time.
In this case, the stone is released from rest, so the initial velocity u is 0. The acceleration due to gravity g is given as 9.8 m/s², and the time t is 3 seconds.
Substituting these values into the equation gives:
v = 0 + 9.8 * 3 v = 29.4 m/s
So, the velocity of the stone after 3 seconds is 29.4 m/s.
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