Let's denote the tens digit as 'a' and the units digit as 'b'. So, the original number can be represented as 10a + b.

When the digits interchange places, the new number becomes 10b + a.

Adding the original number and the new number gives: (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since the resulting number is a multiple of 11, it is divisible by 11.

So, the correct answer is 11.

Question

Let's denote the tens digit as 'a' and the units digit as 'b'. So, the original number can be represented as 10a + b.

When the digits interchange places, the new number becomes 10b + a.

Adding the original number and the new number gives: (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since the resulting number is a multiple of 11, it is divisible by 11.

So, the correct answer is 11.

Knowee AI · Accepted Answer

Let's denote the tens digit as 'a' and the units digit as 'b'. So, the original number can be represented as 10a + b.

When the digits interchange places, the new number becomes 10b + a.

Adding the original number and the new number gives: (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since the resulting number is a multiple of 11, it is divisible by 11.

So, the correct answer is 11.

A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by: Options : 9 11 13 none