Let's assume the original number is represented by the digits "a" and "b". According to the given condition, if we interchange the digits, the resulting number would be represented by the digits "b" and "a".

So, the original number can be written as 10a + b, and the number formed by interchanging the digits can be written as 10b + a.

Now, if we add these two numbers together, we get (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since 11 is a prime number, for the sum to be divisible by 11, (a + b) must be divisible by 11.

Therefore, the answer is option 911.

Question

Let's assume the original number is represented by the digits "a" and "b". According to the given condition, if we interchange the digits, the resulting number would be represented by the digits "b" and "a".

So, the original number can be written as 10a + b, and the number formed by interchanging the digits can be written as 10b + a.

Now, if we add these two numbers together, we get (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since 11 is a prime number, for the sum to be divisible by 11, (a + b) must be divisible by 11.

Therefore, the answer is option 911.

Knowee AI · Accepted Answer

Let's assume the original number is represented by the digits "a" and "b". According to the given condition, if we interchange the digits, the resulting number would be represented by the digits "b" and "a".

So, the original number can be written as 10a + b, and the number formed by interchanging the digits can be written as 10b + a.

Now, if we add these two numbers together, we get (10a + b) + (10b + a) = 11a + 11b = 11(a + b).

Since 11 is a prime number, for the sum to be divisible by 11, (a + b) must be divisible by 11.

Therefore, the answer is option 911.

NumbersA number consists of two digits. If the number formed by interchanging the digits is added to the original number, the resulting number (i.e. the sum) must be divisible byOptions91153

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