\frac{9x}{4}-5=\frac{7}{4}

Sure, let's solve the equation step by step.

1. First, let's isolate the term with the variable on one side of the equation. To do this, we add 5 to both sides of the equation:

   $\frac{9x}{4} - 5 + 5 = \frac{7}{4} + 5$

   This simplifies to:

   $\frac{9x}{4} = \frac{7}{4} + 5$

2. Now, let's convert 5 into a fraction with 4 as the denominator so we can add it to $\frac{7}{4}$. We know that 5 is equivalent to $\frac{20}{4}$, so we substitute 5 with $\frac{20}{4}$:

   $\frac{9x}{4} = \frac{7}{4} + \frac{20}{4}$

3. Now, we add the fractions on the right side of the equation:

   $\frac{9x}{4} = \frac{27}{4}$

4. Finally, to solve for x, we multiply both sides of the equation by the reciprocal of $\frac{9}{4}$, which is $\frac{4}{9}$:

   $\frac{9x}{4} * \frac{4}{9} = \frac{27}{4} * \frac{4}{9}$

   This simplifies to:

   $x = \frac{27}{9}$

5. Simplifying the right side gives us the solution:

   $x = 3$

So, the solution to the equation $\frac{9x}{4} - 5 = \frac{7}{4}$ is $x = 3$.