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The domain of a function g(x) is x > 3, and the range is y > 1. What are the domain and range of its inverse function, 𝑔−1(𝑥)g −1 (x)?A.Domain: x > 1Range: y > 3B.Domain: x > 3Range: y > 1C.Domain: x < 1Range: y < 3D.Domain: x < 3Range: y < 1SUBMITarrow_backPREVIOUS

Question

The domain of a function g(x) is x > 3, and the range is y > 1. What are the domain and range of its inverse function, 𝑔−1(𝑥)g −1 (x)?A.Domain: x > 1Range: y > 3B.Domain: x > 3Range: y > 1C.Domain: x < 1Range: y < 3D.Domain: x < 3Range: y < 1SUBMITarrow_backPREVIOUS

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Solution

The domain and range of a function and its inverse are swapped. So, if the domain of g(x) is x > 3 and the range is y > 1, then for the inverse function, 𝑔−1(𝑥), the domain will be x > 1 and the range will be y > 3. Therefore, the correct answer is A. Domain: x > 1, Range: y > 3.

Similar Questions

The domain of a function h(x) is x > 3, and the range is y ≥ –2. What are the domain and range of its inverse function, h–1(x)?A.Domain: x > –2Range: y > 3B.Domain: x ≥ –2Range: y > 3C.Domain: x > 3Range: y ≥ –2D.Domain: x ≥ 3Range: y > –2SUBMITarrow_backPREVIOUS

The domain of an inverse function is the range of the original function.

Given a function: 𝑓(𝑥) = 𝑥2 + 2.a. Does 𝑓(𝑥) has an inverse for all values of 𝑥.b. Find a possible largest domain where 𝑓(𝑥) has an inverse. Then find the inversefunction 𝑓−1(𝑥).c. What is the domain and range of 𝑓−1(𝑥)

Which one of the following sets is a possible domain for the function with rule f(x)=(x+3)2−6𝑓(𝑥)=(𝑥+3)2−6 if the inverse function is to exist?

1. (2 points) What is the domain of g(x) = arccos(x − 3)?A. (−∞, ∞)B. [−1, 1]C. [−4, −2]D. (−4, −2)E. [2, 4]

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