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The domain of a function h(x) is x > 3, and the range is y ≥ –2. What are the domain and range of its inverse function, h–1(x)?A.Domain: x > –2Range: y > 3B.Domain: x ≥ –2Range: y > 3C.Domain: x > 3Range: y ≥ –2D.Domain: x ≥ 3Range: y > –2SUBMITarrow_backPREVIOUS

Question

The domain of a function h(x) is x > 3, and the range is y ≥ –2. What are the domain and range of its inverse function, h–1(x)?A.Domain: x > –2Range: y > 3B.Domain: x ≥ –2Range: y > 3C.Domain: x > 3Range: y ≥ –2D.Domain: x ≥ 3Range: y > –2SUBMITarrow_backPREVIOUS

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Solution

The domain and range of a function and its inverse are swapped. So, if the domain of h(x) is x > 3 and the range is y ≥ –2, then the domain and range of its inverse function, h–1(x), would be:

Domain: x ≥ –2 Range: y > 3

So, the correct answer is B. Domain: x ≥ –2, Range: y > 3.

Similar Questions

The domain of a function g(x) is x > 3, and the range is y > 1. What are the domain and range of its inverse function, 𝑔−1(𝑥)g −1 (x)?A.Domain: x > 1Range: y > 3B.Domain: x > 3Range: y > 1C.Domain: x < 1Range: y < 3D.Domain: x < 3Range: y < 1SUBMITarrow_backPREVIOUS

The domain of an inverse function is the range of the original function.

Given a function: 𝑓(𝑥) = 𝑥2 + 2.a. Does 𝑓(𝑥) has an inverse for all values of 𝑥.b. Find a possible largest domain where 𝑓(𝑥) has an inverse. Then find the inversefunction 𝑓−1(𝑥).c. What is the domain and range of 𝑓−1(𝑥)

What are the domain and range of the function represented by the set of ordered pairs?{(–3, 2), (–2, 1), (–1, 0), (0, –1)}A.Domain: –3 ≤ x ≤ 0Range: {–1, 0, 1, 2}B.Domain: –3 ≤ x ≤ 0Range: –1 ≤ y ≤ 2C.Domain: {–3, –2, –1, 0}Range: {–1, 0, 1, 2}D.Domain: {–1, 0, 2, 1}Range: {–3, –2, –1, 0}SUBMITarrow_backPREVIOUS

Which one of the following sets is a possible domain for the function with rule f(x)=(x+3)2−6𝑓(𝑥)=(𝑥+3)2−6 if the inverse function is to exist?

1/3

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