A source S1 is producing 1015 photons per second of wavelength 5000˙a . Another sorce S2 is producing 1.02×1015 photons per second of wavelength 5100˙A .Then, (power of S2)/(power of S1) is equal to

The power of a source is given by the equation P = nhv, where n is the number of photons per second, h is Planck's constant, and v is the frequency of the light.

First, we need to convert the wavelength to frequency using the equation v = c/λ, where c is the speed of light and λ is the wavelength.

For S1, the wavelength λ1 = 5000 Å = 5000 * 10^-10 m. So, the frequency v1 = c/λ1 = 3 * 10^8 m/s / (5000 * 10^-10 m) = 6 * 10^14 Hz.

For S2, the wavelength λ2 = 5100 Å = 5100 * 10^-10 m. So, the frequency v2 = c/λ2 = 3 * 10^8 m/s / (5100 * 10^-10 m) = 5.88 * 10^14 Hz.

Next, we substitute these values into the power equation.

The power of S1 is P1 = n1hv1 = (1015 photons/s)(6.63 * 10^-34 J*s)(6 * 10^14 Hz) = 3.978 * 10^-4 W.

The power of S2 is P2 = n2hv2 = (1.02 * 10^15 photons/s)(6.63 * 10^-34 J*s)(5.88 * 10^14 Hz) = 3.89 * 10^-4 W.

Finally, we find the ratio (P2/P1) = (3.89 * 10^-4 W) / (3.978 * 10^-4 W) = 0.9778.

So, the ratio of the power of S2 to the power of S1 is approximately 0.978.