To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency of the light (f) is given as 6×10^14 Hz. Planck's constant (h) is approximately 6.63×10^-34 Js. So, the energy of one photon (E) can be calculated as follows:

E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J

Step 2: Calculate the number of photons per second
The power of the light source is given as 2×10^-3 W. Power is the energy per unit time, so we can find the number of photons emitted per second (N) by dividing the power by the energy of one photon:

N = Power / E = (2×10^-3 J/s) / (3.978×10^-19 J/photon) = 5.03×10^15 photons/s

So, on average, the source emits approximately 5.03×10^15 photons per second.

Question

To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency of the light (f) is given as 6×10^14 Hz. Planck's constant (h) is approximately 6.63×10^-34 Js. So, the energy of one photon (E) can be calculated as follows:

E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J

Step 2: Calculate the number of photons per second
The power of the light source is given as 2×10^-3 W. Power is the energy per unit time, so we can find the number of photons emitted per second (N) by dividing the power by the energy of one photon:

N = Power / E = (2×10^-3 J/s) / (3.978×10^-19 J/photon) = 5.03×10^15 photons/s

So, on average, the source emits approximately 5.03×10^15 photons per second.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency of the light (f) is given as 6×10^14 Hz. Planck's constant (h) is approximately 6.63×10^-34 Js. So, the energy of one photon (E) can be calculated as follows:

E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J

Step 2: Calculate the number of photons per second
The power of the light source is given as 2×10^-3 W. Power is the energy per unit time, so we can find the number of photons emitted per second (N) by dividing the power by the energy of one photon:

N = Power / E = (2×10^-3 J/s) / (3.978×10^-19 J/photon) = 5.03×10^15 photons/s

So, on average, the source emits approximately 5.03×10^15 photons per second.

Monochromatic light of frequency 6×1014 Hz is produced by a laser. The power emitted is 2×10−3 W. How many photons per second on an average, are emitted by the source ?

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