Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?a.64000b. 65,536c.8192d.8000
Question
Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?a.64000b. 65,536c.8192d.8000
Solution
The capacity of a semiconductor memory chip is often given in the format of 'K x N', where 'K' represents the number of memory locations and 'N' represents the number of bits per memory location.
In this case, the chip has a capacity of 8K x 8.
1K is equivalent to 1024 (as it's based on the binary system, where 1K = 2^10). Therefore, 8K is equivalent to 8 x 1024 = 8192 memory locations.
Since each memory location stores 8 bits, and 1 byte is equal to 8 bits, each memory location can store 1 byte of information.
Therefore, the total storage capacity of the chip in bytes is 8192 memory locations x 1 byte per memory location = 8192 bytes.
So, the correct answer is c. 8192.
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