You have been asked to implement 128K X 32 memory unit using 2K X 16. How many memory chips will be required to implement this configuration?Question 8Select one:a.64b.512c.128d.256

To solve this problem, we first need to understand the memory configurations given.

The target memory configuration is 128K X 32. This means we have 128K addresses each of 32 bits.

The available memory chip configuration is 2K X 16. This means each chip has 2K addresses each of 16 bits.

First, let's find out how many chips are needed to match the bit width of the target memory:

The target memory has a bit width of 32 bits, while each available chip has a bit width of 16 bits. Therefore, we need 32/16 = 2 chips to match the bit width of the target memory.

Next, let's find out how many such sets of chips are needed to match the total number of addresses of the target memory:

The target memory has 128K addresses, while each set of chips (as calculated above) has 2K addresses. Therefore, we need 128K/2K = 64 sets of chips to match the total number of addresses of the target memory.

Since each set contains 2 chips (as calculated above), the total number of chips needed is 64 sets * 2 chips/set = 128 chips.

So, the correct answer is c. 128.