The sum of any six consecutive numbers is always divisible by 6.

Here's why:

Let's take six consecutive numbers. We can represent them as n, n+1, n+2, n+3, n+4, n+5.

The sum of these numbers is 6n + 15.

We can factor out a 3 from this expression to get 3(2n + 5).

However, we can't factor out any more numbers to get a 1, 2, 4, or 5.

Therefore, the sum of any six consecutive numbers is always divisible by 6.

Question

The sum of any six consecutive numbers is always divisible by 6.

Here's why:

Let's take six consecutive numbers. We can represent them as n, n+1, n+2, n+3, n+4, n+5.

The sum of these numbers is 6n + 15.

We can factor out a 3 from this expression to get 3(2n + 5).

However, we can't factor out any more numbers to get a 1, 2, 4, or 5.

Therefore, the sum of any six consecutive numbers is always divisible by 6.

Knowee AI · Accepted Answer

The sum of any six consecutive numbers is always divisible by 6.

Here's why:

Let's take six consecutive numbers. We can represent them as n, n+1, n+2, n+3, n+4, n+5.

The sum of these numbers is 6n + 15.

We can factor out a 3 from this expression to get 3(2n + 5).

However, we can't factor out any more numbers to get a 1, 2, 4, or 5.

Therefore, the sum of any six consecutive numbers is always divisible by 6.

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