The sum of the first sixty numbers from one to sixty can be calculated using the formula for the sum of an arithmetic series:

Sum = n/2 * (a + l)

where:
n = number of terms (60 in this case)
a = first term (1 in this case)
l = last term (60 in this case)

So, the sum of the first sixty numbers is:

Sum = 60/2 * (1 + 60) = 30 * 61 = 1830

Now, we need to check which of the given options the sum is divisible by.

1830 ÷ 13 = 140.76923076923077 (not a whole number, so the sum is not divisible by 13)

1830 ÷ 59 = 31.016949152542374 (not a whole number, so the sum is not divisible by 59)

1830 ÷ 60 = 30.5 (not a whole number, so the sum is not divisible by 60)

1830 ÷ 61 = 30 (a whole number, so the sum is divisible by 61)

Therefore, the sum of the first sixty numbers from one to sixty is divisible by 61.

Question

The sum of the first sixty numbers from one to sixty can be calculated using the formula for the sum of an arithmetic series:

Sum = n/2 * (a + l)

where:
n = number of terms (60 in this case)
a = first term (1 in this case)
l = last term (60 in this case)

So, the sum of the first sixty numbers is:

Sum = 60/2 * (1 + 60) = 30 * 61 = 1830

Now, we need to check which of the given options the sum is divisible by.

1830 ÷ 13 = 140.76923076923077 (not a whole number, so the sum is not divisible by 13)

1830 ÷ 59 = 31.016949152542374 (not a whole number, so the sum is not divisible by 59)

1830 ÷ 60 = 30.5 (not a whole number, so the sum is not divisible by 60)

1830 ÷ 61 = 30 (a whole number, so the sum is divisible by 61)

Therefore, the sum of the first sixty numbers from one to sixty is divisible by 61.

Knowee AI · Accepted Answer