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What is the output of this program?       Integer i = new Integer(257);         byte x = i.byteValue();        System.out.print(x);Select one:25710256

Question

What is the output of this program?       Integer i = new Integer(257);         byte x = i.byteValue();        System.out.print(x);Select one:25710256

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Solution

The output of this program will be 1.

Here's the step by step explanation:

  1. An Integer object is created with the value 257.

  2. The byteValue() method is called on the Integer object. This method converts the value of this Integer to a byte.

  3. The byte data type in Java is 8-bit signed two's complement integer, which has a minimum value of -128 and a maximum value of 127 (inclusive).

  4. When 257 is converted to byte, it exceeds the maximum limit of byte. So, it wraps around from the minimum value.

  5. 257 is 1 more than the maximum byte value of 256 (256 is calculated as 128 + 128 - 1), so it wraps around to 1.

  6. The value 1 is printed to the console.

This problem has been solved

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1/3

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