What is The Output of the following    program?  #include<stdio.h>void main(){int  i = printf("00");  int i =printf("00"); printf("%d",i);}000002Garbage value

The code you've provided is written in C language. However, it contains a syntax error. You are declaring the variable 'i' twice.

Here is the corrected version of your code:

#include<stdio.h>
void main(){
    int i = printf("00"); 
    printf("%d",i);
}

The printf function returns the number of characters printed. So, in this case, it prints "00" and returns 2 (the number of characters printed).

So, the output of the corrected program will be:

002

It first prints "00" from the printf("00"), then it prints "2" from the printf("%d",i); because 'i' holds the value 2 which is the number of characters printed by the previous printf statement.