The distance covered by an object starting from rest with uniform acceleration can be calculated using the equation of motion:

d = ut + 0.5at^2

where:
d = distance covered
u = initial velocity
a = acceleration
t = time

In this case, the bike is starting from rest, so the initial velocity (u) is 0. The acceleration (a) is 4 m/s^2 and the time (t) is 5 seconds. Substituting these values into the equation gives:

d = 0*5 + 0.5*4*5^2
d = 0 + 0.5*4*25
d = 0 + 50
d = 50 meters

So, the bike will cover a distance of 50 meters in 5 seconds.

Question

The distance covered by an object starting from rest with uniform acceleration can be calculated using the equation of motion:

d = ut + 0.5at^2

where:
d = distance covered
u = initial velocity
a = acceleration
t = time

In this case, the bike is starting from rest, so the initial velocity (u) is 0. The acceleration (a) is 4 m/s^2 and the time (t) is 5 seconds. Substituting these values into the equation gives:

d = 0*5 + 0.5*4*5^2
d = 0 + 0.5*4*25
d = 0 + 50
d = 50 meters

So, the bike will cover a distance of 50 meters in 5 seconds.

Knowee AI · Accepted Answer

The distance covered by an object starting from rest with uniform acceleration can be calculated using the equation of motion:

d = ut + 0.5at^2

where:
d = distance covered
u = initial velocity
a = acceleration
t = time

In this case, the bike is starting from rest, so the initial velocity (u) is 0. The acceleration (a) is 4 m/s^2 and the time (t) is 5 seconds. Substituting these values into the equation gives:

d = 0*5 + 0.5*4*5^2
d = 0 + 0.5*4*25
d = 0 + 50
d = 50 meters

So, the bike will cover a distance of 50 meters in 5 seconds.

A racing bike has uniform acceleration of 4m/s -2 then distance will it cover in 5 s after the starting from rest is

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