The volume of a rectangular box is 130 cubic inches. The height of the box is 1 inch. The width of the box is 3 inches less than the length.Which equation can you use to find w, the width of the box in inches?1(w–3)=130w(w–3)=130w(w+3)=1301(w+3)=130(w+1)(w–3)=130(w+1)(w+3)=130Now, use the equation you picked to find w.w= inchesSubmit
Question
The volume of a rectangular box is 130 cubic inches. The height of the box is 1 inch. The width of the box is 3 inches less than the length.Which equation can you use to find w, the width of the box in inches?1(w–3)=130w(w–3)=130w(w+3)=1301(w+3)=130(w+1)(w–3)=130(w+1)(w+3)=130Now, use the equation you picked to find w.w= inchesSubmit
Solution
The volume of a rectangular box is given by the formula V = lwh, where l is the length, w is the width, and h is the height.
Given that the volume V is 130 cubic inches, the height h is 1 inch, and the width w is 3 inches less than the length l, we can substitute these values into the formula to get:
130 = l * (l - 3) * 1
Simplifying this equation gives:
130 = l^2 - 3l
This is the equation you can use to find w, the width of the box in inches.
To solve for l, you would need to solve this quadratic equation. However, this equation does not factor nicely, so you would need to use the quadratic formula:
l = [3 ± sqrt((3)^2 - 41(-130))] / (2*1) l = [3 ± sqrt(9 + 520)] / 2 l = [3 ± sqrt(529)] / 2 l = [3 ± 23] / 2
So the possible values for l are l = 13 or l = -10. Since a length cannot be negative, we discard -10 and are left with l = 13 inches.
Then, since the width w is 3 inches less than the length, we have w = l - 3 = 13 - 3 = 10 inches.
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