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The area of a rectangle is 1,056 square inches. Its length is 4 inches longer than 2 times its width.Which equation can you use to find the width of the rectangle, w?1,056=2w(4+w)1,056=w(4+2w)What is the width of the rectangle?

Question

The area of a rectangle is 1,056 square inches. Its length is 4 inches longer than 2 times its width.Which equation can you use to find the width of the rectangle, w?1,056=2w(4+w)1,056=w(4+2w)What is the width of the rectangle?

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Solution

The correct equation to use is 1,056 = w(4+2w). This is because the length is 4 inches longer than 2 times the width, so the length can be represented as (4+2w). The area of a rectangle is found by multiplying the length by the width, hence the equation 1,056 = w(4+2w).

To find the width of the rectangle, we need to solve this equation for w.

First, distribute the w on the right side of the equation:

1,056 = 4w + 2w^2

Rearrange the equation to set it equal to zero:

0 = 2w^2 + 4w - 1,056

To make the equation easier to solve, divide every term by 2:

0 = w^2 + 2w - 528

This is a quadratic equation in the form of 0 = ax^2 + bx + c. We can solve it using the quadratic formula, which is w = [-b ± sqrt(b^2 - 4ac)] / (2a). In this case, a = 1, b = 2, and c = -528.

w = [-2 ± sqrt((2)^2 - 41(-528))] / (2*1) w = [-2 ± sqrt(4 + 2112)] / 2 w = [-2 ± sqrt(2116)] / 2 w = [-2 ± 46] / 2

So the possible solutions are w = 22 or w = -24.

Since the width cannot be negative, the width of the rectangle is 22 inches.

This problem has been solved

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