How much energy is generated from freezing 2.5 g water?A.2.5 g 1 mol/18.02 g (285.83) kJ/molB.2.5 g 1 mol/18.02 g 40.65 kJ/molC.2.5 g 1 mol/18.02 g 4.186 kJ/molD.2.5 g 1 mol/18.02 g (6.03) kJ/molSUBMITarrow_backPREVIOUS
Question
How much energy is generated from freezing 2.5 g water?A.2.5 g 1 mol/18.02 g (285.83) kJ/molB.2.5 g 1 mol/18.02 g 40.65 kJ/molC.2.5 g 1 mol/18.02 g 4.186 kJ/molD.2.5 g 1 mol/18.02 g (6.03) kJ/molSUBMITarrow_backPREVIOUS
Solution
The question is asking how much energy is generated from freezing 2.5 g of water. To answer this, we need to use the heat of fusion of water, which is the amount of energy needed to change 1 g of water from the liquid to the solid state without changing its temperature. The heat of fusion for water is approximately 334 J/g.
Here are the steps to solve this:
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Convert grams of water to moles. The molar mass of water is approximately 18.02 g/mol. So, 2.5 g of water is 2.5 g * (1 mol/18.02 g) = 0.1387 mol.
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Multiply the moles of water by the heat of fusion (in kJ, since the options are in kJ). The heat of fusion for water is approximately 6.01 kJ/mol. So, the energy generated is 0.1387 mol * 6.01 kJ/mol = 0.833 kJ.
So, none of the options A, B, C, or D are correct. The correct answer should be approximately 0.833 kJ.
Similar Questions
Question 2 of 10Constants for waterHvap 40.65 kJ/molHf -285.83 kJ/molHfusion 6.03 kJ/molspecific heat 4.186 J/gCmolar mass 18.02 gHow much energy is released when 6.0 g of water is condensed from water vapor?A.6.0 g 1 mol/18.02 g 6.03 kJ/molB.6.0 g 1 mol/18.02 g 40.65 kJ/molC.6.0 g 1 mol/18.02 g (-285.83 kJ/mol)D.6.0 g 1 mol/18.02 g 4.186 kJ/molSUBMITarrow_backPREVIOUS
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