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Calculate the change in entropy associated with freezing of 0.072 mol of C2 H 5 OHat 158.7 K given that the enthalpy of freezing is 4.60 kJ mol-1 .

Question

Calculate the change in entropy associated with freezing of 0.072 mol of C2 H 5 OHat 158.7 K given that the enthalpy of freezing is 4.60 kJ mol-1 .

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Solution

To calculate the change in entropy (ΔS), we can use the formula:

ΔS = ΔH/T

where ΔH is the change in enthalpy and T is the absolute temperature.

Given in the problem, we have:

ΔH = 4.60 kJ/mol = 4600 J/mol (since 1 kJ = 1000 J) T = 158.7 K

Substituting these values into the formula, we get:

ΔS = 4600 J/mol / 158.7 K = 28.97 J/mol·K

So, the change in entropy associated with the freezing of 0.072 mol of C2H5OH at 158.7 K is 28.97 J/mol·K.

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