The number of electrons passing through a cross-section of a conductor per second can be calculated using the formula:

I = n*q*A

where:
I is the current,
n is the number of electrons,
q is the charge of an electron, and
A is the cross-sectional area of the conductor.

In this case, we are given I = 4.8 A and we know that the charge of an electron, q, is approximately 1.6 x 10^-19 C. We want to find n, the number of electrons. The cross-sectional area, A, does not matter in this case because we are looking for the number of electrons passing through any cross-section per second.

Rearranging the formula to solve for n gives us:

n = I / q

Substituting the given values into this equation gives us:

n = 4.8 A / 1.6 x 10^-19 C

This calculation gives us approximately 3 x 10^19 electrons. Therefore, the number of electrons passing through any cross-section of the conductor per second is approximately 3 x 10^19.

Question

The number of electrons passing through a cross-section of a conductor per second can be calculated using the formula:

I = n*q*A

where:
I is the current,
n is the number of electrons,
q is the charge of an electron, and
A is the cross-sectional area of the conductor.

In this case, we are given I = 4.8 A and we know that the charge of an electron, q, is approximately 1.6 x 10^-19 C. We want to find n, the number of electrons. The cross-sectional area, A, does not matter in this case because we are looking for the number of electrons passing through any cross-section per second.

Rearranging the formula to solve for n gives us:

n = I / q

Substituting the given values into this equation gives us:

n = 4.8 A / 1.6 x 10^-19 C

This calculation gives us approximately 3 x 10^19 electrons. Therefore, the number of electrons passing through any cross-section of the conductor per second is approximately 3 x 10^19.

Knowee AI · Accepted Answer

The number of electrons passing through a cross-section of a conductor per second can be calculated using the formula:

I = n*q*A

where:
I is the current,
n is the number of electrons,
q is the charge of an electron, and
A is the cross-sectional area of the conductor.

In this case, we are given I = 4.8 A and we know that the charge of an electron, q, is approximately 1.6 x 10^-19 C. We want to find n, the number of electrons. The cross-sectional area, A, does not matter in this case because we are looking for the number of electrons passing through any cross-section per second.

Rearranging the formula to solve for n gives us:

n = I / q

Substituting the given values into this equation gives us:

n = 4.8 A / 1.6 x 10^-19 C

This calculation gives us approximately 3 x 10^19 electrons. Therefore, the number of electrons passing through any cross-section of the conductor per second is approximately 3 x 10^19.

A current of 4.8 A is flowing in a conductor. The number of electrons passing through anycross-section per second is

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