A current of 1 A is drawn by a filament of an electric bulb. Numberof electrons passing through a cross section of the filament in 16seconds would be roughl
Question
A current of 1 A is drawn by a filament of an electric bulb. Numberof electrons passing through a cross section of the filament in 16seconds would be roughl
Solution
To find the number of electrons passing through a cross section of the filament, we need to use the formula:
Q = It
where Q is the total charge, I is the current, and t is the time.
Given that the current I is 1 A and the time t is 16 seconds, we can substitute these values into the formula to find the total charge Q:
Q = 1 A * 16 s = 16 C
We know that the charge of one electron is approximately 1.6 x 10^-19 C. Therefore, the number of electrons n can be found by dividing the total charge Q by the charge of one electron e:
n = Q / e = 16 C / 1.6 x 10^-19 C = 1 x 10^20
Therefore, the number of electrons passing through a cross section of the filament in 16 seconds is approximately 1 x 10^20.
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