The average of four consecutive even numbers is 11. Find the largest number.

Sure, here are the steps to solve the problem:

1. Let's denote the four consecutive even numbers as n, n+2, n+4, n+6. They are consecutive even numbers because the difference between each pair of consecutive even numbers is 2.

2. According to the problem, the average of these four numbers is 11. The average is calculated by adding all the numbers together and dividing by the number of numbers. So, we can set up the following equation: (n + n+2 + n+4 + n+6) / 4 = 11.

3. Simplify the equation: 4n + 12 = 44.

4. Solve for n: 4n = 32, so n = 8.

5. The largest number in the sequence is n+6, so the largest number is 8+6 = 14.