If the average of 4 consecutive odd numbers is 60. What is the product of largest and smallest number among these four numbers?

Sure, here is the step by step solution:

Step 1: Understand the problem We know that the average of 4 consecutive odd numbers is 60. We need to find the product of the largest and smallest number among these four numbers.

Step 2: Find the numbers The average of 4 numbers is the sum of those numbers divided by 4. So, the sum of these 4 numbers is 60 * 4 = 240.

Since these are consecutive odd numbers, let's assume the numbers are (x-3), (x-1), (x+1), (x+3). The sum of these numbers is 4x, which is 240. So, x = 240 / 4 = 60.

So, the numbers are 57, 59, 61, and 63.

Step 3: Find the product of the smallest and largest numbers The smallest number is 57 and the largest number is 63. So, the product is 57 * 63 = 3591.

So, the product of the largest and smallest number among these four numbers is 3591.

Sure, here is the step by step solution:

1. Let's denote the four consecutive odd numbers as a, a+2, a+4, a+6. They are consecutive odd numbers because odd numbers always have a difference of 2.

2. The average of these four numbers is given as 60. The average is calculated by adding all the numbers and dividing by the quantity of numbers. So, (a + a+2 + a+4 + a+6) / 4 = 60.

3. Simplifying the above equation gives 4a + 12 = 240.

4. Solving for 'a' gives a = 57. So, the four numbers are 57, 59, 61, 63.

5. The product of the smallest and largest numbers is 57 * 63 = 3591.

So, the product of the smallest and largest numbers among these four numbers is 3591.