The product of following reaction isCH3 – CH = CH – CH2 – CHO i) LiAlH4+ii) H O3→
Question
The product of following reaction isCH3 – CH = CH – CH2 – CHO i) LiAlH4+ii) H O3→
Solution
To determine the product of the given reaction, we need to follow the steps of the reaction mechanism.
Step 1: LiAlH4 (lithium aluminum hydride) is a strong reducing agent that can reduce aldehydes and ketones to alcohols. In this case, LiAlH4 will reduce the aldehyde (CHO) group to an alcohol (CH2OH).
CH3 – CH = CH – CH2 – CHO + LiAlH4 → CH3 – CH = CH – CH2 – CH2OH
Step 2: H2O3 (ozone) is a powerful oxidizing agent that can cleave carbon-carbon double bonds. In this case, H2O3 will cleave the double bond between the second and third carbon atoms.
CH3 – CH = CH – CH2 – CH2OH + H2O3 → CH3 – CH = CH2 + CH3CHO + H2O
Therefore, the product of the given reaction is CH3 – CH = CH2 (propene) and CH3CHO (acetaldehyde), along with the formation of water (H2O).
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