Four men and two women can do a piece of work together in one day. If a woman is twice as efficient as a man, in how many days can a woman working alone do the work?
Question
Four men and two women can do a piece of work together in one day. If a woman is twice as efficient as a man, in how many days can a woman working alone do the work?
Solution
Let's solve this step by step:
Step 1: Let's assume the work done by a man in one day is m and the work done by a woman in one day is w. According to the problem, a woman is twice as efficient as a man, so we can say w = 2m.
Step 2: According to the problem, four men and two women can complete the work in one day. So, we can write this as 4m + 2w = 1 (since the total work is considered as 1 unit).
Step 3: Substitute w = 2m into the equation from step 2, we get 4m + 2(2m) = 1, which simplifies to 8m = 1. So, the work done by a man in one day (m) is 1/8.
Step 4: Since a woman is twice as efficient as a man, the work done by a woman in one day (w) is 2m = 2(1/8) = 1/4.
Step 5: If a woman can do 1/4 of the work in one day, then a woman can do the entire work alone in 4 days.
So, a woman working alone can do the work in 4 days.
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