12 men can complete any work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only the women were to complete the remaining work in 4 days, then how many women would be required? 60 74 68 70
Question
12 men can complete any work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only the women were to complete the remaining work in 4 days, then how many women would be required? 60 74 68 70
Solution
The problem can be solved in the following steps:
Step 1: Find the work done by one man in one day and one woman in one day.
According to the problem, 12 men can complete the work in 36 days. So, the work done by one man in one day is 1/(12*36).
Similarly, 18 women can complete the work in 60 days. So, the work done by one woman in one day is 1/(18*60).
Step 2: Find the total work done by 8 men and 20 women in 20 days.
The work done by 8 men in 20 days is 820/(1236) and the work done by 20 women in 20 days is 2020/(1860).
Adding these two, we get the total work done in 20 days.
Step 3: Subtract the work done in 20 days from the total work to find the remaining work.
The total work is 1 (as it is the whole work). So, the remaining work is 1 - (work done in 20 days).
Step 4: Find the number of women required to complete the remaining work in 4 days.
Let's say the number of women required is W. So, W women can do the remaining work in 4 days. Therefore, W4/(1860) = remaining work.
Solving this equation will give us the value of W, which is the number of women required to complete the remaining work in 4 days.
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