A man lent out Rs.7200 partly at 5% simple interest and the rest at 12% simple interest. The total interest earned after years was Rs.1440. Find the ratio of sums lent at 5% and 12% respectively.
Question
A man lent out Rs.7200 partly at 5% simple interest and the rest at 12% simple interest. The total interest earned after years was Rs.1440. Find the ratio of sums lent at 5% and 12% respectively.
Solution
Let's denote the sum lent at 5% as x and the sum lent at 12% as (7200 - x).
The total interest earned after one year is the sum of the interests earned from both parts of the sum. So, we can write the equation:
0.05x + 0.12(7200 - x) = 1440
Solving this equation will give us the value of x, which is the sum lent at 5%. The sum lent at 12% is then 7200 - x.
Finally, we can find the ratio of the sums lent at 5% and 12% by dividing x by (7200 - x).
Let's solve the equation:
0.05x + 0.12(7200 - x) = 1440 0.05x + 864 - 0.12x = 1440 0.07x = 576 x = 576 / 0.07 x = 8228.57
But x cannot be greater than 7200, so there seems to be a mistake in the problem. The total interest earned after one year cannot be Rs.1440 if the total sum lent is Rs.7200 and the interest rates are 5% and 12%. Please check the problem again.
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