Let's denote the sum lent at 6% per annum as x and the sum lent at 8% per annum as y.

According to the problem, we know that:

x + y = 12,000 (since the total sum is Rs. 12,000)

We also know that the total interest after 1 year is Rs. 860. The interest is calculated as (principal * rate * time), so we can write:

0.06x + 0.08y = 860 (since the interest from the first sum is 6% and from the second sum is 8%)

Now we have a system of two equations, and we can solve it step by step.

First, let's express y from the first equation:

y = 12,000 - x

Now we can substitute y in the second equation:

0.06x + 0.08(12,000 - x) = 860

Solving this equation gives:

0.06x + 960 - 0.08x = 860

-0.02x = -100

x = 5000

Substituting x = 5000 in the first equation gives:

5000 + y = 12,000

y = 7000

So, the sum lent at 8% per annum is Rs. 7000.

Question

Let's denote the sum lent at 6% per annum as x and the sum lent at 8% per annum as y.

According to the problem, we know that:

x + y = 12,000 (since the total sum is Rs. 12,000)

We also know that the total interest after 1 year is Rs. 860. The interest is calculated as (principal * rate * time), so we can write:

0.06x + 0.08y = 860 (since the interest from the first sum is 6% and from the second sum is 8%)

Now we have a system of two equations, and we can solve it step by step.

First, let's express y from the first equation:

y = 12,000 - x

Now we can substitute y in the second equation:

0.06x + 0.08(12,000 - x) = 860

Solving this equation gives:

0.06x + 960 - 0.08x = 860

-0.02x = -100

x = 5000

Substituting x = 5000 in the first equation gives:

5000 + y = 12,000

y = 7000

So, the sum lent at 8% per annum is Rs. 7000.

Knowee AI · Accepted Answer