Evaluate –k2 – (3k – 5n) + 4n; k = −1 and n = −2.

Sure, let's solve this step by step:

First, let's substitute the values of k and n into the equation.

So, –k^2 – (3k – 5n) + 4n becomes -(-1)^2 - (3*(-1) - 5*(-2)) + 4*(-2).

Now, let's simplify this:

-(-1)^2 becomes -1 (since -1 squared is 1, and the negative sign in front makes it -1).

3*(-1) becomes -3, and -5*(-2) becomes 10. So, (3k – 5n) becomes (-3 + 10) which is 7.

4*(-2) becomes -8.

So, the equation now is -1 - 7 - 8.

Finally, if you add these together, you get -16. So, the solution to the equation –k^2 – (3k – 5n) + 4n when k = −1 and n = −2 is -16.