The problem involves drawing two marbles with replacement, which means after drawing a marble, it is put back into the bag before the next draw. This means the total number of marbles in the bag remains the same for both draws.

Step 1: Determine the total number of marbles in the bag. There are 6 green marbles and 4 red marbles, so there are 6 + 4 = 10 marbles in total.

Step 2: Determine the probability of drawing a green marble. There are 6 green marbles out of a total of 10 marbles, so the probability of drawing a green marble is 6/10 or 0.6.

Step 3: Since the marbles are drawn with replacement, the probability of drawing a green marble on the second draw is also 0.6.

Step 4: The probability of both events happening (drawing a green marble on the first draw and drawing a green marble on the second draw) is the product of the probabilities of each event. So, the probability of drawing a green marble on both draws is 0.6 * 0.6 = 0.36.

So, the answer is not in the options given. The probability of drawing a green marble on both draws is 0.36.

Question

The problem involves drawing two marbles with replacement, which means after drawing a marble, it is put back into the bag before the next draw. This means the total number of marbles in the bag remains the same for both draws.

Step 1: Determine the total number of marbles in the bag. There are 6 green marbles and 4 red marbles, so there are 6 + 4 = 10 marbles in total.

Step 2: Determine the probability of drawing a green marble. There are 6 green marbles out of a total of 10 marbles, so the probability of drawing a green marble is 6/10 or 0.6.

Step 3: Since the marbles are drawn with replacement, the probability of drawing a green marble on the second draw is also 0.6.

Step 4: The probability of both events happening (drawing a green marble on the first draw and drawing a green marble on the second draw) is the product of the probabilities of each event. So, the probability of drawing a green marble on both draws is 0.6 * 0.6 = 0.36.

So, the answer is not in the options given. The probability of drawing a green marble on both draws is 0.36.

Knowee AI · Accepted Answer

The problem involves drawing two marbles with replacement, which means after drawing a marble, it is put back into the bag before the next draw. This means the total number of marbles in the bag remains the same for both draws.

Step 1: Determine the total number of marbles in the bag. There are 6 green marbles and 4 red marbles, so there are 6 + 4 = 10 marbles in total.

Step 2: Determine the probability of drawing a green marble. There are 6 green marbles out of a total of 10 marbles, so the probability of drawing a green marble is 6/10 or 0.6.

Step 3: Since the marbles are drawn with replacement, the probability of drawing a green marble on the second draw is also 0.6.

Step 4: The probability of both events happening (drawing a green marble on the first draw and drawing a green marble on the second draw) is the product of the probabilities of each event. So, the probability of drawing a green marble on both draws is 0.6 * 0.6 = 0.36.

So, the answer is not in the options given. The probability of drawing a green marble on both draws is 0.36.

In a bag, there are 6 green marbles and 4 red marbles. If two marbles are drawn with replacement, what is the probability of drawing a green marble on both draws?a.0.24b.0.33c.0.46d.0.52

Question

Solution

Similar Questions

Upgrade your grade with Knowee