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Find the inverse of the matrix A = [2 5; 1 3].a.[3 1; -5 2]b.[3 -5; -1 2]c.[2 -5; 1 3]d.[3 -1; -5 2]

Question

Find the inverse of the matrix A = [2 5; 1 3].a.[3 1; -5 2]b.[3 -5; -1 2]c.[2 -5; 1 3]d.[3 -1; -5 2]

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Solution

To find the inverse of a 2x2 matrix A = [a b; c d], we use the formula:

A^(-1) = 1/(ad-bc) * [d -b; -c a]

Given the matrix A = [2 5; 1 3], let's calculate its inverse:

First, calculate the determinant (ad-bc): (23) - (51) = 6 - 5 = 1

Then, swap the positions of a and d, and change the signs of b and c:

[d -b; -c a] = [3 -5; -1 2]

Finally, multiply by 1/(ad-bc):

A^(-1) = 1/1 * [3 -5; -1 2] = [3 -5; -1 2]

So, the inverse of the matrix A = [2 5; 1 3] is [3 -5; -1 2], which corresponds to option (b).

This problem has been solved

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