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answerWhat will be the output of the following Java program? class array_value { public static void main(String args[]) { int array_variable [] = new int[20]; for (int v = 10; v < 20; ++v) { array_variable[v] = v/2; array_variable[v]++; System.out.print(array_variable[v] + " "); v++; }  } }Options10 12 14 16 1810 11 12 13 14 15 16 17 18 196 7 8 9 1010 11 12 13 14 15 16 17 18 19 20

Question

answerWhat will be the output of the following Java program? class array_value { public static void main(String args[]) { int array_variable [] = new int[20]; for (int v = 10; v < 20; ++v) { array_variable[v] = v/2; array_variable[v]++; System.out.print(array_variable[v] + " "); v++; }  } }Options10 12 14 16 1810 11 12 13 14 15 16 17 18 196 7 8 9 1010 11 12 13 14 15 16 17 18 19 20

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Solution

The output of the Java program will be "6 7 8 9 10".

Here's the step-by-step explanation:

  1. An integer array named array_variable of size 20 is declared.
  2. A for loop is initiated where the variable v starts from 10 and goes up to 19 (since the condition is v < 20).
  3. Inside the loop, the vth element of the array is assigned the value of v/2. Since v and 2 are integers, the division will also result in an integer (the fractional part, if any, will be discarded). So, for v = 10, v/2 will be 5, for v = 11, v/2 will be 5, for v = 12, v/2 will be 6, and so on.
  4. The vth element of the array is then incremented by 1. So, the values become 6, 6, 7, 7, 8, 8, 9, 9, 10, 10 for v = 10 to v = 19.
  5. The vth element of the array is then printed. However, after each print, v is incremented by 1 again due to the v++ statement. This means that every alternate value is printed, starting from v = 10. So, the output will be "6 7 8 9 10".
  6. The loop then continues until v is less than 20.

This problem has been solved

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