Here is a Python program that meets the requirements:

```python
def find_digits(n):
min_odd = 10
max_even = -1
while n 0:
digit = n % 10
if digit % 2 == 0:
max_even = max(max_even, digit)
else:
min_odd = min(min_odd, digit)
n = n // 10
if min_odd == 10:
print("There are no odd digits in the number.")
else:
print("Minimum odd digit:", min_odd)
if max_even == -1:
print("There are no even digits in the number.")
else:
print("Maximum even digit:", max_even)

# Test the function
find_digits(3465)
find_digits(97975)
find_digits(24642)
```

This program defines a function `find_digits` that takes an integer `n` as input. It initializes `min_odd` to 10 and `max_even` to -1. Then it enters a while loop that continues as long as `n` is greater than 0. In each iteration of the loop, it calculates the current digit by taking the remainder of `n` divided by 10. If the digit is even, it updates `max_even` if the digit is greater than the current `max_even`. If the digit is odd, it updates `min_odd` if the digit is less than the current `min_odd`. Then it removes the last digit from `n` by doing integer division by 10. After the loop, it checks if `min_odd` is still 10, which means there were no odd digits, and if `max_even` is still -1, which means there were no even digits, and prints appropriate messages. Otherwise, it prints the minimum odd digit and the maximum even digit.

Question

Here is a Python program that meets the requirements:

```python
def find_digits(n):
    min_odd = 10
    max_even = -1
    while n > 0:
        digit = n % 10
        if digit % 2 == 0:
            max_even = max(max_even, digit)
        else:
            min_odd = min(min_odd, digit)
        n = n // 10
    if min_odd == 10:
        print("There are no odd digits in the number.")
    else:
        print("Minimum odd digit:", min_odd)
    if max_even == -1:
        print("There are no even digits in the number.")
    else:
        print("Maximum even digit:", max_even)

# Test the function
find_digits(3465)
find_digits(97975)
find_digits(24642)
```

This program defines a function `find_digits` that takes an integer `n` as input. It initializes `min_odd` to 10 and `max_even` to -1. Then it enters a while loop that continues as long as `n` is greater than 0. In each iteration of the loop, it calculates the current digit by taking the remainder of `n` divided by 10. If the digit is even, it updates `max_even` if the digit is greater than the current `max_even`. If the digit is odd, it updates `min_odd` if the digit is less than the current `min_odd`. Then it removes the last digit from `n` by doing integer division by 10. After the loop, it checks if `min_odd` is still 10, which means there were no odd digits, and if `max_even` is still -1, which means there were no even digits, and prints appropriate messages. Otherwise, it prints the minimum odd digit and the maximum even digit.

Knowee AI · Accepted Answer

Here is a Python program that meets the requirements:

```python
def find_digits(n):
    min_odd = 10
    max_even = -1
    while n > 0:
        digit = n % 10
        if digit % 2 == 0:
            max_even = max(max_even, digit)
        else:
            min_odd = min(min_odd, digit)
        n = n // 10
    if min_odd == 10:
        print("There are no odd digits in the number.")
    else:
        print("Minimum odd digit:", min_odd)
    if max_even == -1:
        print("There are no even digits in the number.")
    else:
        print("Maximum even digit:", max_even)

# Test the function
find_digits(3465)
find_digits(97975)
find_digits(24642)
```

This program defines a function `find_digits` that takes an integer `n` as input. It initializes `min_odd` to 10 and `max_even` to -1. Then it enters a while loop that continues as long as `n` is greater than 0. In each iteration of the loop, it calculates the current digit by taking the remainder of `n` divided by 10. If the digit is even, it updates `max_even` if the digit is greater than the current `max_even`. If the digit is odd, it updates `min_odd` if the digit is less than the current `min_odd`. Then it removes the last digit from `n` by doing integer division by 10. After the loop, it checks if `min_odd` is still 10, which means there were no odd digits, and if `max_even` is still -1, which means there were no even digits, and prints appropriate messages. Otherwise, it prints the minimum odd digit and the maximum even digit.

Question

Solution

Similar Questions

Upgrade your grade with Knowee