The kinetic energy of an object can be calculated using the formula KE = 1/2mv^2, where m is the mass of the object and v is its velocity.

When the balls are dropped from the building, they both start with an initial velocity of 0 m/s. As they fall, they accelerate due to gravity. The acceleration due to gravity is approximately 9.8 m/s^2.

After falling 30m, we can calculate the velocity of the balls using the equation of motion v^2 = u^2 + 2gs, where u is the initial velocity, g is the acceleration due to gravity, and s is the distance.

For both balls, u = 0 m/s, g = 9.8 m/s^2, and s = 30m.

So, v^2 = 0 + 2*9.8*30 = 588 m^2/s^2.

Therefore, v = sqrt(588) = 24.25 m/s.

Now, we can calculate the kinetic energy of each ball.

For the 2kg ball, KE = 1/2*2*(24.25)^2 = 588 J.

For the 4kg ball, KE = 1/2*4*(24.25)^2 = 1176 J.

Therefore, the ratio of the kinetic energies of the 2kg ball to the 4kg ball is 588:1176 = 1:2.

Question

The kinetic energy of an object can be calculated using the formula KE = 1/2mv^2, where m is the mass of the object and v is its velocity.

When the balls are dropped from the building, they both start with an initial velocity of 0 m/s. As they fall, they accelerate due to gravity. The acceleration due to gravity is approximately 9.8 m/s^2.

After falling 30m, we can calculate the velocity of the balls using the equation of motion v^2 = u^2 + 2gs, where u is the initial velocity, g is the acceleration due to gravity, and s is the distance.

For both balls, u = 0 m/s, g = 9.8 m/s^2, and s = 30m.

So, v^2 = 0 + 2*9.8*30 = 588 m^2/s^2.

Therefore, v = sqrt(588) = 24.25 m/s.

Now, we can calculate the kinetic energy of each ball.

For the 2kg ball, KE = 1/2*2*(24.25)^2 = 588 J.

For the 4kg ball, KE = 1/2*4*(24.25)^2 = 1176 J.

Therefore, the ratio of the kinetic energies of the 2kg ball to the 4kg ball is 588:1176 = 1:2.

Knowee AI · Accepted Answer

The kinetic energy of an object can be calculated using the formula KE = 1/2mv^2, where m is the mass of the object and v is its velocity.

When the balls are dropped from the building, they both start with an initial velocity of 0 m/s. As they fall, they accelerate due to gravity. The acceleration due to gravity is approximately 9.8 m/s^2.

After falling 30m, we can calculate the velocity of the balls using the equation of motion v^2 = u^2 + 2gs, where u is the initial velocity, g is the acceleration due to gravity, and s is the distance.

For both balls, u = 0 m/s, g = 9.8 m/s^2, and s = 30m.

So, v^2 = 0 + 2*9.8*30 = 588 m^2/s^2.

Therefore, v = sqrt(588) = 24.25 m/s.

Now, we can calculate the kinetic energy of each ball.

For the 2kg ball, KE = 1/2*2*(24.25)^2 = 588 J.

For the 4kg ball, KE = 1/2*4*(24.25)^2 = 1176 J.

Therefore, the ratio of the kinetic energies of the 2kg ball to the 4kg ball is 588:1176 = 1:2.

A ball of mass 2kg and another of mass 4kg are dropped together from a 60m tall building. After a fall of 30m each towards earth, their respective kinetic energies will be in the ratio of __________.1:11:21:31:4

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