The momentum of an object is given by the product of its mass and velocity (p=mv). When an object falls from a height, it gains velocity due to acceleration caused by gravity. The velocity (v) gained can be calculated using the equation v = sqrt(2gh), where g is the acceleration due to gravity and h is the height from which the object falls.

Given that the ratio of the masses of the two balls is 1:2 and the ratio of the heights from which they fall is 1:4, we can calculate the ratio of their velocities as follows:

For the first ball, let's denote its mass as m1 and the height from which it falls as h1. For the second ball, let's denote its mass as m2 and the height from which it falls as h2.

Given that m1/m2 = 1/2 and h1/h2 = 1/4, we can calculate the ratio of their velocities as v1/v2 = sqrt(h1/h2) = sqrt(1/4) = 1/2.

Therefore, the ratio of their momenta (p1/p2) is (m1*v1)/(m2*v2) = (1/2 * 1/2) / (2 * 1/2) = 1/2.

So, the ratio of their momenta with which they strike the ground is 1:2.

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The momentum of an object is given by the product of its mass and velocity (p=mv). When an object falls from a height, it gains velocity due to acceleration caused by gravity. The velocity (v) gained can be calculated using the equation v = sqrt(2gh), where g is the acceleration due to gravity and h is the height from which the object falls.

Given that the ratio of the masses of the two balls is 1:2 and the ratio of the heights from which they fall is 1:4, we can calculate the ratio of their velocities as follows:

For the first ball, let's denote its mass as m1 and the height from which it falls as h1. For the second ball, let's denote its mass as m2 and the height from which it falls as h2.

Given that m1/m2 = 1/2 and h1/h2 = 1/4, we can calculate the ratio of their velocities as v1/v2 = sqrt(h1/h2) = sqrt(1/4) = 1/2.

Therefore, the ratio of their momenta (p1/p2) is (m1*v1)/(m2*v2) = (1/2 * 1/2) / (2 * 1/2) = 1/2.

So, the ratio of their momenta with which they strike the ground is 1:2.

Knowee AI · Accepted Answer

The momentum of an object is given by the product of its mass and velocity (p=mv). When an object falls from a height, it gains velocity due to acceleration caused by gravity. The velocity (v) gained can be calculated using the equation v = sqrt(2gh), where g is the acceleration due to gravity and h is the height from which the object falls.

Given that the ratio of the masses of the two balls is 1:2 and the ratio of the heights from which they fall is 1:4, we can calculate the ratio of their velocities as follows:

For the first ball, let's denote its mass as m1 and the height from which it falls as h1. For the second ball, let's denote its mass as m2 and the height from which it falls as h2.

Given that m1/m2 = 1/2 and h1/h2 = 1/4, we can calculate the ratio of their velocities as v1/v2 = sqrt(h1/h2) = sqrt(1/4) = 1/2.

Therefore, the ratio of their momenta (p1/p2) is (m1*v1)/(m2*v2) = (1/2 * 1/2) / (2 * 1/2) = 1/2.

So, the ratio of their momenta with which they strike the ground is 1:2.

Two balls of masses in the ratio 1: 2 fall from heights in the ratio 1: 4. The ratio of their momenta with which they strike the ground is01:101:201:301:411:50 pm

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