Max is listening to music on his phone while doing yard work. After 1 hour, his phone's battery had a charge of 68%. If the battery drains at a constant rate of x percent per hour, how much charge will it have after 3 hours?4x–6868–4x2x–683x–6868–2x68–3xSubmit
Question
Max is listening to music on his phone while doing yard work. After 1 hour, his phone's battery had a charge of 68%. If the battery drains at a constant rate of x percent per hour, how much charge will it have after 3 hours?4x–6868–4x2x–683x–6868–2x68–3xSubmit
Solution
The problem states that Max's phone battery drains at a constant rate of x percent per hour. After 1 hour, the battery had a charge of 68%. This means that the phone started with a battery charge of 100% and after 1 hour of use, it drained x percent. So, we can write this as:
100% - x = 68%
Solving for x gives us:
x = 100% - 68% = 32%
This means the phone's battery drains at a rate of 32% per hour.
Now, we want to know how much charge the phone will have after 3 hours. Since the battery drains at a constant rate, we can calculate this as:
68% (charge after 1 hour) - 2*32% (charge drained in the next 2 hours) = 68% - 64% = 4%
So, after 3 hours, the phone will have a charge of 4%.
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