Last year Rachel invested money in two accounts. The first account had an interest rate of 6%6% and the second account had an interest rate of 4%4%. If she invested $800$800 more in the first account than the second and her total interest income was $238$238, how much did she invest at each rate?Step 2 of 3: Use the table from part 1 to help write a linear equation that represents the given word problem. (Use x to represent the unknown quantity.) Do not simplify your answer.
Question
Last year Rachel invested money in two accounts. The first account had an interest rate of 6%6% and the second account had an interest rate of 4%4%. If she invested 800 more in the first account than the second and her total interest income was 238, how much did she invest at each rate?Step 2 of 3: Use the table from part 1 to help write a linear equation that represents the given word problem. (Use x to represent the unknown quantity.) Do not simplify your answer.
Solution
Let's denote the amount of money Rachel invested in the second account as x. Therefore, the amount of money she invested in the first account is x + $800.
Since the total interest income was $238, we can write the following equation:
0.06 * (x + 238
This equation represents the total interest income from both accounts. The term 0.06 * (x + $800) represents the interest from the first account and the term 0.04 * x represents the interest from the second account.
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