What is the value of ๐ฆy when ๐ฆ=3๐ฅ2+2๐ฅโ5y=3x 2 +2xโ5 and ๐ฅ=โ1x=โ1?
Question
What is the value of ๐ฆy when ๐ฆ=3๐ฅ2+2๐ฅโ5y=3x 2 +2xโ5 and ๐ฅ=โ1x=โ1?
Solution
To find the value of y, we need to substitute x = -1 into the equation y = 3x^2 + 2x - 5.
Step 1: Substitute x = -1 into the equation y = 3(-1)^2 + 2(-1) - 5
Step 2: Simplify the equation y = 3(1) - 2 - 5 y = 3 - 2 - 5
Step 3: Solve the equation y = -4
Similar Questions
To find the ๐ฆy value of the equation ๐ฆ=5๐ฅy=5x when ๐ฅ=โ1x=โ1:Given the equation:๐ฆ=5๐ฅy=5xSubstitute ๐ฅ=โ1x=โ1 into the equation:๐ฆ=5(โ1)y=5(โ1)๐ฆ=โ5y=โ5So, the ๐ฆy value when ๐ฅ=โ1x=โ1 is โ5โ5.
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