When ๐(๐ฅ) = 3๐ฅ โ 5 and ๐(๐ฅ) = 2๐ฅ2 โ 5 , find ๐(๐(๐ฅ))
Question
When ๐(๐ฅ) = 3๐ฅ โ 5 and ๐(๐ฅ) = 2๐ฅ2 โ 5 , find ๐(๐(๐ฅ))
Solution
To find the composition of the functions ๐(๐(๐ฅ)), we substitute ๐(๐ฅ) into ๐(๐ฅ).
Step 1: Write down the function ๐(๐ฅ) = 3๐ฅ โ 5
Step 2: Substitute ๐(๐ฅ) = 2๐ฅยฒ - 5 into ๐(๐ฅ). Wherever there is an ๐ฅ in the function ๐, replace it with ๐(๐ฅ).
So, ๐(๐(๐ฅ)) = 3(๐(๐ฅ)) - 5 = 3(2๐ฅยฒ - 5) - 5
Step 3: Simplify the expression.
๐(๐(๐ฅ)) = 6๐ฅยฒ - 15 - 5 = 6๐ฅยฒ - 20
So, ๐(๐(๐ฅ)) = 6๐ฅยฒ - 20.
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