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25t 2 +20t+3=−1

Question

25t 2 +20t+3=−1

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Solution

Sure, let's solve the equation step by step:

  1. First, rewrite the equation: 25t^2 + 20t + 3 = -1
  2. Move -1 to the left side of the equation: 25t^2 + 20t + 3 + 1 = 0
  3. Simplify the equation: 25t^2 + 20t + 4 = 0
  4. This is a quadratic equation in the form of at^2 + bt + c = 0. We can solve it using the quadratic formula: t = [-b ± sqrt(b^2 - 4ac)] / (2a)
  5. Substitute a, b, and c into the formula: t = [-20 ± sqrt((20)^2 - 4254)] / (2*25)
  6. Simplify the equation: t = [-20 ± sqrt(400 - 400)] / 50
  7. Further simplify: t = [-20 ± sqrt(0)] / 50
  8. Solve for t: t = -20 / 50 = -0.4

So, the solution to the equation 25t^2 + 20t + 3 = -1 is t = -0.4.

This problem has been solved

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10t−22=−5(−2t+3)

b. 3t2 + 24t + 45 = 0

20 – 3(2 + t) = 2t + 4

−5x−3x 2 =20

3(−2x−1)+x−2=25

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