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Find the slope of f(x)𝑓(𝑥) at x=2𝑥=2. The graph of f(x)𝑓(𝑥) is shown below.Move the point on the curve to x=2𝑥=2. Then plot two points on the tangent line. Finally, calculate the slope of f(x)𝑓(𝑥) at x=2𝑥=2. Write your answer as a simplified fraction or rounded to 44 decimal places.

Question

Find the slope of f(x)𝑓(𝑥) at x=2𝑥=2. The graph of f(x)𝑓(𝑥) is shown below.Move the point on the curve to x=2𝑥=2. Then plot two points on the tangent line. Finally, calculate the slope of f(x)𝑓(𝑥) at x=2𝑥=2. Write your answer as a simplified fraction or rounded to 44 decimal places.

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Solution

Para encontrar la pendiente de f(x) f(x) en x=2 x = 2 , sigue estos pasos:

  1. Identificar el punto en la curva:

    • Mueve el punto en la curva de f(x) f(x) hasta x=2 x = 2 .
    • Supongamos que el punto en la curva en x=2 x = 2 es (2,f(2)) (2, f(2)) .
  2. Dibujar la línea tangente:

    • Dibuja la línea tangente a la curva en el punto (2,f(2)) (2, f(2)) .
  3. Seleccionar dos puntos en la tangente:

    • Elige dos puntos en la línea tangente. Supongamos que estos puntos son (x1,y1) (x_1, y_1) y (x2,y2) (x_2, y_2) .
  4. Calcular la pendiente de la tangente:

    • La pendiente m m de la línea tangente se calcula usando la fórmula de la pendiente: m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}
  5. Simplificar la pendiente:

    • Simplifica la fracción resultante o redondea el resultado a 4 decimales.

Por ejemplo, si los puntos en la tangente son (1,3) (1, 3) y (3,7) (3, 7) , la pendiente sería: m=7331=42=2 m = \frac{7 - 3}{3 - 1} = \frac{4}{2} = 2

Por lo tanto, la pendiente de f(x) f(x) en x=2 x = 2 es 2.

This problem has been solved

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