Find the function whose tangent has slope 𝑥 3 − 2 𝑥 2 + 16 for each of x and whose graph passes through the point (2,5).
Question
Find the function whose tangent has slope 𝑥 3 − 2 𝑥 2
- 16 for each of x and whose graph passes through the point (2,5).
Solution 1
The function whose tangent has a given slope is the integral of that slope. The slope given is x^3 - 2x^2 + 16.
Step 1: Integrate the slope function to find the original function.
∫(x^3 - 2x^2 + 16) dx = (1/4)x^4 - (2/3)x^3 + 16x + C
This is the general form of the function. The constant C can be found by using the point that the function passes through.
Step 2: Substitute the point (2,5) into the function and solve for C.
5 = (1/4)(2)^4 - (2/3)(2)^3 + 16(2) + C 5 = 4 - 16/3 + 32 + C 5 = 36/3 - 16/3 + 96/3 + C 5 = 116/3 + C
Step 3: Solve for C.
C = 5 - 116/3 = 15/3 - 116/3 = -101/3
So, the function is f(x) = (1/4)x^4 - (2/3)x^3 + 16x - 101/3.
Solution 2
The function whose tangent has a given slope is the integral of that slope. The slope given here is x^3 - 2x^2 + 16.
Step 1: Integrate the slope function to find the original function.
∫(x^3 - 2x^2 + 16) dx = (1/4)x^4 - (2/3)x^3 + 16x + C
Here, C is the constant of integration.
Step 2: To find the value of C, use the point (2,5) which lies on the function.
Substitute x = 2 and y = 5 into the equation:
5 = (1/4)(2)^4 - (2/3)(2)^3 + 16(2) + C
Solve the above equation for C.
After solving, you will get the value of C and the complete function.
Solution 3
The function whose tangent has a given slope is the integral of that slope. The slope given here is x^3 - 2x^2 + 16.
Step 1: Integrate the slope function to find the original function.
∫(x^3 - 2x^2 + 16) dx = (1/4)x^4 - (2/3)x^3 + 16x + C
This is the general form of the function. The constant C is determined by the condition that the graph passes through the point (2,5).
Step 2: Substitute x = 2 and y = 5 into the equation to solve for C.
5 = (1/4)(2)^4 - (2/3)(2)^3 + 16(2) + C 5 = 4 - 16/3 + 32 + C 5 = 36/3 + C 5 - 12 = C C = -7
So, the function is y = (1/4)x^4 - (2/3)x^3 + 16x - 7.
Solution 4
The function whose tangent has a given slope is the integral of that slope. The slope given is x^3 - 2x^2 + 16.
Step 1: Integrate the slope function to find the original function.
∫(x^3 - 2x^2 + 16) dx = (1/4)x^4 - (2/3)x^3 + 16x + C
This is the general form of the function. The constant C is determined by the condition that the graph passes through the point (2,5).
Step 2: Substitute x = 2 and y = 5 into the equation to solve for C.
5 = (1/4)(2)^4 - (2/3)(2)^3 + 16(2) + C 5 = 4 - 16/3 + 32 + C 5 = 36/3 + C 5 - 36/3 = C C = -6
So, the function is y = (1/4)x^4 - (2/3)x^3 + 16x - 6.
Similar Questions
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